Arrange the digits from 1 to 9 to make a 9-digit number ABCDEFGHI which satisfies the following conditions: 1) AB is divisible by 2; 2) ABC is divisible by 3; 3) ABCD is divisible by 4; 4) ABCDE is divisible by 5; 5) ABCDEF is divisible by 6; 6) ABCDEFG is divisible by 7; 7) ABCDEFGH is divisible by 8; 8) ABCDEFGHI is divisible by 9. My Dear Friends,Here is the solution for the aboveFrom condition 4, we know that E equals 5. From conditions 1, 3, 5 and 7, we know that B, D, F, H are even numbers, therefore A, C, G, I are 1, 3, 7, 9 in some order. Furthermore, from conditions 3 and 7 we know that CD is divisible by 4 and GH is divisible by 8 (because FGH is divisible by 8 and F is even). Because C and G are odd, D and H must be 2 and 6 in some order. From conditions 2 and 5, we know that A+B+C, D+E+F, G+H+I are all divisible by 3. If D=2, then F=8, H=6, B=4. A+4+C is divisible by 3, therefore A and C must be 1 and 7 in some order, G and I must be 3 and 9 in some order. G6 is divisible by 8, therefore G=9. But neither 1472589 nor 7412589 is divisible by 7. Therefore D=6, and F=4, H=2, B=8. G2 is divisible by 8, therefore G=3 or 7. A+8+C is divisible by 3, therefore one of A and C is chosen from 1 and 7, the other is chosen from 3 and 9. If G=3, then one of A and C is 9, the other is chosen from 1 and 7. But none of 1896543, 7896543, 9816543 and 9876543 is divisible by 7. Therefore G=7, one of A and C is 1, the other is chosen from 3 and 9. From 1836547, 1896547, 3816547 and 9816547, only 3816547 is divisible by 7 (the quotient is 545221). Therefore, the number we are looking for is 381654729 |

## Saturday, April 9, 2011

### Little HARD Puzzle

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